Question

An airplane takes off
at an angle of 60°.
If muzzle velocity of the plane is 200 km/hr, calculate its horizontal and vertical components.

please help me guys, ASAP
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Answer 1

Answer:

Here v=200kmh−1,θ=60∘

∴Horizontal component

vx=vcosθ=200cos60∘

=200×12=100Kmh−1

Vertical component

vy=vsinθ=200sin60∘=200×3–√2=1003–√Kmh−1