An airplane takes off at angle 30 to the horizontal. If the component of it's velocity along the horizontal is 250km/hr . What is the actual velocity? Also find the vertical component of the velocity .
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Explanation:
there are two components:v cos theta and vsin theta
A.T.Q horizintal component=v costheta=250km/hr given
v×cos 30 =250km/hr
then v=500/(3^1/2)=actual velocity vertical component =v sin theta
v×sin30=[500/(3^1/2)]×1/2
=250/(3^1/2).
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