An airplane taking off from a field has a run of 500m . what is the acceleration and take off velocity if it leaves the ground 10 seconds after the start
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Explanation:
DISTANCE = s=500m
Initial velocity =u=0 m/s
Final velocity =V=?
Time=t=10s
From Second equation of motion:
S=ut + 1/2at^2
500=0*10 +1/2 *a 100
a=500/50=10m/s2
From V= u+ at
=0+10*10
=100m/ s
Therefore , acceleration is 10m/ s2 and take off velocity is 100m/s.
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