Question

An airplane touches down at 225 km/h and stops after 2 min . Calculate the run away .​

Answer 1

Answer:

Step-by-step explanation:

See the initial velocity(u) of the aeroplane will be 216 km/h = 60 m/s

Final velocity (v) = 0 m/s

And displacement till it comes to rest is 2000m

So by using formula

V^2 - U^2 = 2as

0 - 3600 = 2a(2000)

Hence a = - 0.9 m/s^2

So by using formula v-u=at

We get 0–60 =- 0.9t

Hence t is approximately 66.67 seconds

Answer 2

Answer:

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Step-by-step explanation:

it is approximately 66.67 seconds