An airthmatic series has a first term 5 with a common difference of 3. Find the 100th term of the series
Answers
Answered by
2
Step-by-step explanation:
xn=dn+f-d
=3n+5-3
=3n+2
x100=3×100+2
=302
Answered by
1
Answer:
Given = A = 5
d = 3
a>n=a+(n-1)d
=5+(100-1)3
=5+99×3
=5+297
a>100 =302
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