An alcohol ‘B’ when treated with conc. H2SO4 gives compound ‘C’. compound ‘C’ when reacted with Hydrogen bromide produces compound ‘D’. compound ‘D’ when reacted with sodium in presence of ether gives C4H10.
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Answer:
A:CH
3
CH
2
−OH
B:CH
3
−CH
2
−O−CH
2
−CH
3
C:CH
2
=CH
2
CH
3
CH
2
−OH+Na⟶CH
3
CH
2
−0Na+H
2
↑
H
2
SO
4
CH
8
CH
2
−OH⟶CH
3
CH
2
−O−CH
2
CH
3
413K
H
2
SO
4
CH
3
CH
2
−OH⟶CH
2
=CH
2
443K
Br
2
CH
2
CH
2
⟶ Bromine water decolourises.
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