Question

an alfa - particleof

mass 6. 4x10 kg and
change 3.2 x10 c is situated in a uniform
electric field of 1. 6x10vm The Velocity of the particle at the end of 2(10) m path when it starts fr rest is
f
2710 m path when
it starts from nest
Particle at the end
2.
is​

Answer 1

Explanation:

1\2mv ^=q(e)(s)

v=[2qes /m]=

{[2(3.2)(16)(1.6)(10)(2)(10)]} / 0.4(10)

v=4(2)(10)m/s