An algebra textbook has a total of 1382 pages. It is broken up into two parts. The second part of the book has 64 pages more than the first part. How many pages are in each part of the book?
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Answered by
19
The first part is x and the second part will be x +62
Therefore
1382=x+x+62
1382-62=2x
1320/2=x
x=660
The first part is 660
The second part is 724
Therefore
1382=x+x+62
1382-62=2x
1320/2=x
x=660
The first part is 660
The second part is 724
veenaprasadd:
this is wrong
Answered by
5
First part is x and the second part will be x + 64. Therefore 1382=×+×64. Sub ract 64 1382-62=2×. 1320÷2=×. ×=660. The first part is 660 and the second part 660+64=724
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