Question

An algebra textbook has a total of 1382 pages. It is broken up into two parts. The second part of the book has 64 pages more than the first part. How many pages are in each part of the book?

Answer 1

Let number of pages in 1st part is x
and number of pages in 2nd part is y.

because total number of pages in algebra textbook is 1382 .
so, x + y = 1382.......(1)

a/c to question,
second part of the book has 64 pages more than 1st part .
e.g., y = 64 + x .........(ii)

put equation (ii) in equation (i),
=> x + 64 + x = 1382
=> 2x + 64 = 1382
=> 2x = 1382 - 64 = 1318
=> x = 659

put x = 659 in equation (ii),
y = 64 + 659 = 723.

hence, number of pages in 1st part is 659
number of pages in 2nd part is 723

Answer 2

SOLUTION :   Let the number of pages in first part of text book be x & number of pages in second part be y. Given :  Total number of pages in algebra textbook = 1382 . First part + second part = 1382 x + y = 1382………........(1)   A.T.Q Given : Second part of the book has 64 pages more than 1st part . y = 64 + x   x - y = - 64..................(2) On Adding eq 1 & eq 2 x - y = - 64. x + y = 1382 ------------------- 2x = 1318 x = 1318/2   x = 659 On Putting x = 659 in equation (2),   x - y = - 64 659 - y = -64 y = 64 + 659 = 723 y = 623   Hence,the number of pages in first part is 659 and number of pages in second part is 723.    HOPE THIS ANSWER WILL HELP YOU...