Question

An alkali metal A gtves a compound B (molecular mass 9/10
reacting with water. Ihe compound B gives a soluble compo
C on treatment with aluminium oxide, Identi$' A. B and C and
give the reaction involved

Answer 1

Answer:

A is sodium because molar mass of NaOH is 40; which can be shown as follows:

Na(23)+O(16)+H(I)=40

So. B is NaOH

When sodium hydroxide is treated with aluminium oxide, we get sodium aluminate. So, C is sodium aluminate. Following reaction happens in this case:

Al2O3 +2NaOH→2NaAlO2+H20

Explanation:

hope it helps you

Answer 2

Explanation:

given:-

A. +H2O -------->. B (molecular mass 0.9)

B + Al2O3-----------> C

I just didn't this is right question

because of molecular mass.

how is it possible to have 0.9 molecular mass