Chemistry, asked by samruddhi26jadhav, 3 months ago

An alkene 'A' contains three c-c eight c-H sigma bonds and one c-c bond 'A' on ozonolysis​

Answers

Answered by akshank610
0

Answer:

Explanation:

AS THERE ARE 3 C-C,8 C-H AND 1 C=C BONDS ,THEN THE STRUCTURE IS

BUT-2- ENE

CH3-CH=CH-CH3

ON OZONOLYSIS

CH3-CH=CH-CH3+O3⇒CH3CHO+CH3CHO

THE PRODUCTS ARE =2CH3CHO

THIS PRODUCT 2CH3CHO IS CALLED AS-METHANAL

SO BUT-2-ENE ON OZONOLYSIS GIVEN 2 MOLES OF METHANAL

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