Chemistry, asked by nishantshukla2971, 1 year ago

an alkene 'A' of molcular mass 28u on treatment with bromine gives a product 'B' The compound 'B'on further Dehalogenation with zinc gives back A​

Answers

Answered by CHAMPION009
1

Answer:

Reaction with Zn

CH

2

Br−CH

2

Br+Zn→CH

2

=CH

2

+ZnBr

2

Reaction with alc. KOH

Br−H

2

C−CH

2

−Br

AlcoholicKOH

1,2−dibromo ethane(vic−dihalide)

H

2

C=CH−Br

NaNH

2

CH≡CH+NaBr+NH

3

Explanation:

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