an alkene 'A' of molcular mass 28u on treatment with bromine gives a product 'B' The compound 'B'on further Dehalogenation with zinc gives back A
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Answer:
Reaction with Zn
CH
2
Br−CH
2
Br+Zn→CH
2
=CH
2
+ZnBr
2
Reaction with alc. KOH
Br−H
2
C−CH
2
−Br
AlcoholicKOH
1,2−dibromo ethane(vic−dihalide)
H
2
C=CH−Br
NaNH
2
CH≡CH+NaBr+NH
3
Explanation:
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