An alkene having molecular formula C₇H₁₄ was
subjected to ozonolysis in the presence of zinc
dust. An equimolar amount of the following two
compounds was obtained
CH₃ and CH₃
＼ ＼
C = O C = O
／ ／
CH₃ CH₃CH₂
The IUPAC name of the alkene is
(a) 3, 4-dimethyl-3-pentene
(b) 3, 4-dimethyl-2-pentene
(c) 2, 3-dimethyl-3-pentene
(d) 2, 3-dimethyl-2-pentene
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Answer:
option B
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The IUPAC name of the alkene is (d) 2, 3-dimethyl-2-pentene
Explanation:
From question, the chemical equation of the reaction is attached in the image below.
C₃H₆O + C₄H₈O → C₇H₁₄
CH₃ CH₃
＼ ／
C = C
／ ＼
CH₃ CH₂ - CH₃
For IUPAC naming, the carbon atoms in the linear chain should be numbered.
There are 5 carbon. Thus, it is 'pentane'.
It has double bond. Thus, 'pentene'.
The bond is attached between second and third carbon atoms. Thus, '2-pentene'.
The methyl group is attached to both second and third carbon atoms. Thus, '2, 3-dimethyl'.
Therefore, the IUPAC name of the compound is 2, 3-dimethyl-2-pentene.
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