Question

An alkene having molecular formula C₇H₁₄ was
subjected to ozonolysis in the presence of zinc
dust. An equimolar amount of the following two
compounds was obtained
CH₃ and CH₃
＼ ＼
C = O C = O
／ ／
CH₃ CH₃CH₂
The IUPAC name of the alkene is
(a) 3, 4-dimethyl-3-pentene
(b) 3, 4-dimethyl-2-pentene
(c) 2, 3-dimethyl-3-pentene
(d) 2, 3-dimethyl-2-pentene

Answer 1

Answer:

option B

IT WILL DEFINITELY HELP U

Answer 2

The IUPAC name of the alkene is (d) 2, 3-dimethyl-2-pentene

Explanation:

From question, the chemical equation of the reaction is attached in the image below.

C₃H₆O + C₄H₈O → C₇H₁₄

CH₃                         CH₃

       ＼              ／

             C = C

        ／             ＼

CH₃                          CH₂ - CH₃

For IUPAC naming, the carbon atoms in the linear chain should be numbered.

There are 5 carbon. Thus, it is 'pentane'.

It has double bond. Thus, 'pentene'.

The bond is attached between second and third carbon atoms. Thus, '2-pentene'.

The methyl group is attached to both second and third carbon atoms. Thus, '2, 3-dimethyl'.

Therefore, the IUPAC name of the compound is 2, 3-dimethyl-2-pentene.