An alkyl halide by formation of Grignard's reagent
followed by hydrolysis yield butane. What is the
original alkyl halide?
(1) Ethyl halide (2) Propyl halide
(3) Butyl halide (4) Methyl halide
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The original alkyl hallide is (3) Butyl halide.
●On reaction with alkyl halide with magnesium metal we get magnesium alkyl halide that is gignard reagent.
●On hydrolysis this gignard reagent gives alkane.
●We get butane as final product so alkyl halide should be butyl halide.
●Butyl halide with magnesium gives Mgbutylhalide that is MgRX which is gignard reagent ,this on hydrolysis gives butane and Mg(OH)X.
●Reactions are as follow---
RX+Mg--->RMgX(gignard reagent)
CH3CH2CH2CH2Cl+Mg----->CH3CH2CH2CH2MgCl(Gignard)
RMgX+H2O-------.>RH(Mg(OH)Cl
CH3CH2CH2CH2MgCl+H2O------>Ch3CH2CH2CH3+Mg(OH)Cl
So alkyl halide is butyl halide
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