An alloy consist of 27one by 2 kg of copper and 2 three by 4 kg of tin.find the ration by weight of tin to alloy
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Answered by
49
Given" Alloy consists of 27 1/2 kg of copper and 2 3/4 kg of time"
Total weight of alloy = 27 1/2 + 2 3/4
= 55/2 + 11/4
=2(55) + 11 /4
=110+11/4
=121/4 kg
=30.25 kg
we can write it as ...
= 30 1/4 kg is the total weight..
Now Weight of Tin = 2 3/4 kg..
Ratio by weight of Tin to alloy is..
(2 3/4) / (30 1/4)
(11/4) / (121/4)
(!1×4) /(4×121)
(1/11)....or 1 : 11 is the Ratio by weight of Tin to Alloy
Total weight of alloy = 27 1/2 + 2 3/4
= 55/2 + 11/4
=2(55) + 11 /4
=110+11/4
=121/4 kg
=30.25 kg
we can write it as ...
= 30 1/4 kg is the total weight..
Now Weight of Tin = 2 3/4 kg..
Ratio by weight of Tin to alloy is..
(2 3/4) / (30 1/4)
(11/4) / (121/4)
(!1×4) /(4×121)
(1/11)....or 1 : 11 is the Ratio by weight of Tin to Alloy
Answered by
19
Answer:
Step-by-step explanation:
Cu=27 1/2 kg=55/2kg
Sn= 2 3/4kg=11/4 kg
Wt(tin:alloy)=?
Wt. of alloy=(55/2) + (11/4) =121/4
B/Q
(11/4)÷(121/4)
=1/11
Thus, answer=1:11
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