Question

· An alloy consists of 13 parts of copper to 7 parts of zinc and 5 parts of nickel. What is the percentage
composition of the alloy ?
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Answer 1

Answer:

Total parts = 13 + 7 + 5 = 25 . Percentage composition of nickel = 5/25×100 = 20%

Step-by-step explanation:

Since this question is from Chemistry of Chapter - Is matter around us pure?

Parts of Copper = 13

Parts of Zinc = 7

Parts of Nickel = 5

Total part of Alloy = 13+7+5 = 25

Percentage of Copper(Cu) =( Value of Component/ Total Value x 100)%

percentage \: = \frac{13}{25} \times 100percentage=2513×100

percentage \: = 13 \times 4 = 52\%percentage=13×4=52%

Again,

Percentage of Zinc(Zn) = 7/25 x 100 %

percentage \: = 7 \times 4 = 28\%percentage=7×4=28%

Now,

Percentage of Nickel (Ni) = 5/25 x 100 %

percentage \: = 5 \times 4 = 20\%percentage=5×4=20%

Answer 2

Total Parts of Alloy = 13+7+5 => 25

% of Copper = $\sf{\dfrac{13}{25}\times 100 = 13\times4=52\%}$

% of Zinc = $\sf{\dfrac{7}{25}\times100=7\times4=28\%}$

% of Nickel = $\sf{\dfrac{5}{25}\times100=5\times4=20\%}$

Therefore, the total percent adds up to 100%.

So,

% of Copper = 52%

% of Zinc = 28%

% of Nickel = 20%

Hope it helps u

Have a great day ahead

Annyeong