Question

an alloy consists of 13 parts of copper to 7 parts of zinc and 5 parts nickel what is the percentage composition of alloy?? plz solve this in a proper way step by step​

Answer 1

Total Parts of Alloy = 13+7+5 => 25

% of Copper = $\sf{\dfrac{13}{25}\times 100 = 13\times4=52\%}$

% of Zinc = $\sf{\dfrac{7}{25}\times100=7\times4=28\%}$

% of Nickel = $\sf{\dfrac{5}{25}\times100=5\times4=20\%}$

Therefore, the total percent adds up to 100%.

So,

% of Copper = 52%

% of Zinc = 28%

% of Nickel = 20%

Hope it helps u

Have a great day ahead

Annyeong

Answer 2

Step-by-step explanation:

Composition

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Copper Zinc Nickel

(13 parts) (7 parts) (5 parts)

Total number of Parts => 13+7+5 = 25

% of copper => $\frac{number \: of \: parts \: of \: copper \: \: \times 100}{total \: parts}$

=>$\frac{13 \: \: \times 100}{25}$

=> 52%

% of Zinc => $\frac{7 \: \: \times 100}{25}$

=> 20%

% of Nickel => $\frac{5 \: \: \times 100}{25}$

=> 28%

Therefore, Percentage compostion of the alloy is :

Copper = 52%

Zinc = 28%

Nickel = 20%