Math, asked by shalu33, 1 year ago

An alloy consists of 3 1/2 gm of copper and 2 3/4 gm of tin.find the ratio of copper to that of tin in the alloy in the simplest form

Answers

Answered by JackelineCasarez
148

Answer:

Ratio of the copper to that of tin in the alloy is 14 : 11 .

Step-by-step explanation:

As given

An alloy consists of 3 \frac{1}{2} gm of copper and 2 \frac{3}{4} gm of tin.

It is also written as

An alloy consists of \frac{7}{2} gm of copper and \frac{11}{4} gm of tin.

\frac{Weight\ of\ copper}{Weight\ of\ tin}= \frac{\frac{7}{2}}{\frac{11}{4}}

Simplify the above

\frac{Weight\ of\ copper}{Weight\ of\ tin}= \frac{7\times 4}{2\times 11}

\frac{Weight\ of\ copper}{Weight\ of\ tin}= \frac{7\times 2}{1\times 11}

\frac{Weight\ of\ copper}{Weight\ of\ tin}= \frac{14}{11}

Therefore the ratio of the copper to that of tin in the alloy is 14 : 11 .

Answered by kanchanshivkataria
7

Answer:

14:11 ratio these is right

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