An alloy consists of 3½
gm of copper and 2¾
gm of tin. Find the ratio of copper to that of tin in
the alloy in the simplest form.
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3
Answer:
14/11
Step-by-step explanation:
An alloy consists of 3 \frac{1}{2}321 gm of copper and 2 \frac{3}{4}243 gm of tin.
It is also written as
An alloy consists of \frac{7}{2}27 gm of copper and \frac{11}{4}411 gm of tin.
\frac{Weight\ of\ copper}{Weight\ of\ tin}= \frac{\frac{7}{2}}{\frac{11}{4}}Weight of tinWeight of copper=41127
Simplify the above
\frac{Weight\ of\ copper}{Weight\ of\ tin}= \frac{7\times 4}{2\times 11}Weight of tinWeight of copper=2×117×4
\frac{Weight\ of\ copper}{Weight\ of\ tin}= \frac{7\times 2}{1\times 11}Weight of tinWeight of copper=1×117×2
\frac{Weight\ of\ copper}{Weight\ of\ tin}= \frac{14}{11}Weight of tinWeight of copper=1114
Therefore the ratio of the copper to that of tin in the alloy is 14 : 11
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