An alloy contains 26% of copper. What quantity of alloy is required to get 260 g of copper?
Answers
Answered by
0
Answer:
260/26*100
26*5=130/13=10 Ans
Answered by
6
Answer:
Let the quantity of alloy be = x gm
then, 26% of x = 260 gm
= 26 × x = 260 gm
100
= x = 260 × 100 gm
26
= x = 26000 gm
26
= x = 1000gm
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