Question

An alloy contains 42% tin , 33% ,brass and the rest zinc. Find the amount of zinc in 800 g of this alloy.

Answer 1

Answer:

200 g

Step-by-step explanation:

•Amount of tin = 42 % of the alloy

= 42/100 × 800 g

= 336 g

•Amount of Brass = 33% of the alloy

= 33/100 × 800 g

= 264 g

•Total amount of alloy which is not zinc = 336g + 264 g = 600 g

•Total amount of zinc = 800g - 600g

= 200 g

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