an alloy contains alluminium and zinc in the ratio 5 : 3 and another alloy contains alluminium and copper in the ratio 8 : 5 . if equals weight of both the alloys are mixed together
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Let 104 kg of each be melted.
then copper in the first alloy = 104×5/8 = 65 kg.
Zinc in the first alloy = 104×3/8 = 39 kg.
Copper in 2nd alloy = 104×8/13 = 64 kg.
Tin in 2nd alloy = 104×5/13 = 40 kg.
Total alloy = 104 + 104 = 208 kg.
Weight of tin per kg. = 104×5/ = 65 kg.
40/208=5/26kg.=192gram.
then copper in the first alloy = 104×5/8 = 65 kg.
Zinc in the first alloy = 104×3/8 = 39 kg.
Copper in 2nd alloy = 104×8/13 = 64 kg.
Tin in 2nd alloy = 104×5/13 = 40 kg.
Total alloy = 104 + 104 = 208 kg.
Weight of tin per kg. = 104×5/ = 65 kg.
40/208=5/26kg.=192gram.
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