Chemistry, asked by bhupimeet2165, 11 months ago

An alloy contains copper, zinc and tin in the ratio 4 : 5 : 6 respectively. Another alloy containing copper and tin is melted and mixed with the first alloy. If the mixture contains copper, zinc and tin in the ratio 13 : 1 : 3, find the ratio of copper and tin in the second alloy.

Answers

Answered by riteshbhd003
0

Answer:

Ratio of Zinc, Copper and Tin is given as,

Z : C : T = 2 : 3 : 1.

Now, let the first alloy be 12 kg (taken as 4 kg Zinc, 6 kg Copper and 2 Kg Lead). Weight of second alloy = 12 kg as, C : T : L = 5 : 4 : 3. (taken as 5 kg Copper, 4 kg Tin and 3 Kg Lead.)

Alloys are mixed together to form third alloy. Then the ratio of content in it,

Z : C : T : L = 4 : (6 + 5) : (2 + 4) : 3

Weight of third alloy = 12 + 12 = 24 Kg.

So, weight of the Lead = 324

= 18

kg.

Answered by reddyvivek76
0

Answer:12:5

Explanation:

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