An alloy contains tin n copper in the ratio 4:5.if tin has 20% impurity and copper has 58%,wat is the average impurity?
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Answer:
tin = 4/9 , copper = 5/9
impurity in, tin =4/9 *20% = 8/90 , copper = 5/9 *58% = 29/90
total impurity = (8/90 +29/90) = 37/90
% impurity = 37/90 *100 = 41 % approax
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