An alloy of gold and copper weights 50 g. It contains 80% gold. How much gold should be added to the alloy so that
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gold in 50 gram of alloys .
80×50÷10=40 g
let X gram gold must be added
now according to the questions
40+X /50+X =90/100
100(40+X) =90(50+X)
10 (40 +x) = 9(50 +x )
400+10x=45+9x
80×50/10=40g
x=450_400 =50g
Thus 50 gram of gold must be added to it 90%
80×50÷10=40 g
let X gram gold must be added
now according to the questions
40+X /50+X =90/100
100(40+X) =90(50+X)
10 (40 +x) = 9(50 +x )
400+10x=45+9x
80×50/10=40g
x=450_400 =50g
Thus 50 gram of gold must be added to it 90%
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