Question

An alloy of gold silver and bronze contains 90% of bronze 7% of gold and 3% of silver.

A second alloy of bronze and silver only is melted with first and the mixture contains 85% of bronze 5% of gold and 10% of silver.

Find the percentage of bronze in the second alloy.

Answer 1

Thank you for asking this question. The options for this question are missing. Here are the missing options:

a. 75%

b. 72.5%

c. 70%

d. 67.5%

e. 65%

Answer:

Let A and B the first and second alloy weights respectively

x=% of bronze in alloy B

We know that B contains no GOLD.

.07A=.05(A+B)

B=.4A

substituting,

.9A+.4Ax=.85(A+.4A)

x=.725=72.5%

Option B is the final answer.

If there is any confusion please leave a comment below.

Answer 2

Answer:

72.5%

Step-by-step explanation:

Let A and B the first and second alloy weights respectively

x=% of bronze in alloy B

We know that B contains no GOLD.

.07A=.05(A+B)

B=.4A

substituting,

.9A+.4Ax=.85(A+.4A)

x=.725=72.5%