Question

An alloy of metals X and Y weighs 12 g and contains atoms X and Y in the ratio 2:5. Then % by mass of X in the sample is 20. If atomic mass of X is 40, what is the atomic mass of metal Y???????????

Answer 1

➖Given data is that :-

⭕️Mass of sample of alloy = 12g

⭕️% by mass of metal X in the sample= 20

⭕️∴ if x is the mass of metal X in the sample will be :-
 
⇒ (x/12 ) x 100 = 20

⇒ x = 2.4 g
 
⭕ if y is the mass of metal Y in the sample, then:-

⇒ Y = 12 – 2.4 = 9.6 g
 
⭕️Let m be no. of atoms of metal X in sample

⭕️Let n ️be no. of atoms of metal Y in sample

⭕️Ratio of atoms m and n = 2:5

∴ n = 5/2 m
 
Now,

⭕️m = mass of metal "X" in the sample/ atomic mass of X

= 2.4/40

= 0.06

⇒ So, n = (5/2) x 0.06

= 0.15

0.15 = mass of metal "Y" in the sample/ atomic mass Y

⭕️Atomic mass of Y = 9.6/0.15

= 64 g

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Answer 2

Hey there ____

Answer ________

Mass of sample of alloy = 12 g

% mass of metal X = 20

Metal Of X in sample will be
x/12 * 100 = 2.4 g..

Y in metal Y 40 = 12-2.4=9.6

Let m to the no of atom of X
Let n to the no of atom Y

ratio of atoms = 2:5
n = 5/2

Atomic mass of X

2.4/40 =0.06

n = 5/2*0.06 = 0.15

Atomic mass of Y

9.6/0.15 = 64 g

Thank you