Question

an alloy of silver and copper containing silver and copper in the ratio of 7:3 and another alloy of silver and copper containing silver and copper in 5:1. in what ratio of quantity of both alloy should be mixed together so that 8kg alloy silver will become 75 percent​?​

Answer 1

Step-by-step explanation:

The first alloy contains 3x units of silver and x units of copper for some value of x.

The second alloy contains 5y units of silver and 3y units of copper for some value of y.

Therefore, any mixture of the two alloys will contain 3x + 5y units of silver and x + 3y units of copper.

We require 3x + 5y = 2(x + 3y)

3x + 5y = 2x + 6y

x = y

So the first alloy consists of 3x + x = 4x units and the second alloy consists of 5y + 3y = 8y = 8x units.

The two alloys should be added in the ratio 4x : 8x, that is 1 : 2.

hope this helps