an alloy of silver and gold weighs 30 gm in air and 28 gm in water . assuming that silver loses one-tenth of its weight in water and that gold loses one -ninetenth of its weight,find the weight of each metal in the alloy..
Answers
Answer:
x = 8.8889 gm
y = 21.1111gm
Step-by-step explanation:
Let weight of silver in air be x and that of gold be y
Therefore, x + y = 30 ----> 1
Now in water,
Thus x - x/10 + y - y/19 = 28
=> (171x + 180y)/190 = 28
=> 171x + 180y = 5320 ---->2
Multiplying Eq. 1 by 180 we get
180x + 180y = 5400 ---->3
Subtrating Eq.2 from Eq.3
9x = 80
=> x = 8.8889 gm
Therefore y = 30 - x
=> y = 30 - 8.8889 = 21.1111gm
Answer:
Step-by-step explanation:
Answer:
x = 8.8889 gm
y = 21.1111gm
Step-by-step explanation:
Let weight of silver in air be x and that of gold be y
Therefore, x + y = 30 ----> 1
Now in water,
Thus x - x/10 + y - y/19 = 28
=> (171x + 180y)/190 = 28
=> 171x + 180y = 5320 ---->2
Multiplying Eq. 1 by 180 we get
180x + 180y = 5400 ---->3
Subtrating Eq.2 from Eq.3
9x = 80
=> x = 8.8889 gm
Therefore y = 30 - x
=> y = 30 - 8.8889 = 21.1111gm