Question

an alloy of silver and gold weighs 30g in air and 28 g in water.assuming that silver loses one-tenth of its weight in water and that gold loses one-nineteenth of its weight in water,find the weight of each metal in the alloy
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Answer 1

Step-by-step explanation:

x = 8.8889 gm

y = 21.1111gm

Step-by-step explanation:

Let weight of silver in air be x and that of gold be y

Therefore, x + y = 30 ----> 1

Now in water,

Thus x - x/10 + y - y/19 = 28

=> (171x + 180y)/190 = 28

=> 171x + 180y = 5320 ---->2

Multiplying Eq. 1 by 180 we get

180x + 180y = 5400 ---->3

Subtracting Eq.2 from Eq.3

9x = 80

=> x = 8.8889 gm

Therefore y = 30 - x

=> y = 30 - 8.8889 = 21.1111gm

Hope it helps ^_~