Question

An alloy of zinc and tin contains 35% of zinc by weight. What quantity of zinc must be added
to 400 lb of this alloy such that there is 60% of zinc by weight in the final mixture?
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Answer 1

Answer:

100lb

Step-by-step explanation:

Initial amount of zinc=35% of 400

= 140lb

let x amount of zinc is added to make it's percentage composition to be 60%

then

$\frac{140 + x}{400} \times 100 = 60$

$x = 240 - 140$

x=100

Hope you understand it....

Answer 2

Answer:

it is mixture aligation question

35 100

60

40 25

8:5

5:8=x:400

x=250