Question

an alloys contains zinc , copper and tin in the ratio 2:3:1 and an other contains copper , tin and lead in the ratio 5:4:3 ,if equal weights of both alloys are melted together to form a third ally , then the weight of led per kg in the new alloy will be.​

Answer 1

Answer:

The weight of lead per kg in the new alloy will be 0.125 kg.

Step-by-step explanation:

Alloy-1

Zinc:Copper:tin = 2:3:1

Let the total mass of the an alloy-1 be = 2x+3x+1x= 6x

Alloy-2

Copper : tin : lead = 5:4:3

Let the total mass of alloy-2 be = 5x + 4x + 3x =12x

After mixing of equal mass of both allow the total mas of alloy-3 will becomes:

12 x + 2 × 12x = 24x

Lead present in alloy-3 = 3x

Percentage o lead in alloy-3 =$\frac{3x}{24x}\times 100 =12.5\%$

So, in 1 kg of alloy-3 the weight of the lead will be:$1\times \frac{12.5}{100}=0.125 kg = 125 g$

The weight of lead per kg in the new alloy will be 0.125 kg.

Answer 2

Answer:

an alloys contains zinc , copper and tin in the ratio 2:3:1 and an other contains copper , tin and lead in the ratio 5:4:3 ,if equal weights of both alloys are melted together to form a third ally , then the weight of led per kg in the new alloy will be = 0.125 kg

Step-by-step explanation:

Let say Weight of Each alloy  = 12X kg

in First Alloy

Zinc = 2/(2+3+1) * 12X = 4X kg

Copper = 3/(2+3+1) * 12X = 6X kg

Tin = 1/(2+3+1) * 12X = 2X kg

in Second Alloy

Copper = 5/(5+4+3) * 12X = 5X kg

Tin = 4/(5+4+3) * 12X = 3X kg

Lead = 3/(5+4+3) * 12X = 3X kg

Total weight of Both Alloys = 12X + 12X = 24 X kg

Weight of Lead = 3X kg

Lead Per kg = 3X/24X = 1/8 = 0.125 kg