Question

An alpha nucleus of energy $\frac{1}{2}mv^{2}$ bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to(a) $\frac{1}{Ze}$(b) v²(c)$\frac{1}{m}$(d) $\frac{1}{v^{4}}$

Answer 1

Hey

An alpha nucleus of energy $\frac{1}{2}mv^{2}$ bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to(a) $\frac{1}{Ze}$(b) v²(c)$\frac{1}{m}$(d) $\frac{1}{v^{4}}$

D

Answer 2

An alpha nucleus of energy $\frac{1}{2}mv^{2}$ bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to(a) $\frac{1}{Ze}$(b) v²(c)$\frac{1}{m}$(d) $\frac{1}{v^{4}}$

Answrr - D