Chemistry, asked by ramachandrabir7077, 2 months ago

An alpha particle after passing through a potential difference of V volt collides with a nucleus.If the atomic number of nucleus Z, then the distance of closest approach is_____________________

Answers

Answered by anuradhasingh24834

2

Answer:

14.4z/vA°

Explanation:

r =2×ze×9×10^9/2v=r=2×z×1.6×10^-19×9×10^9 /2v=r=14.4z vA°

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