Question

An alpha particle has a de broglie wavelength lambda when it is accelerated yhrough a potential difference of v vots. To have the same wavelength a proton should be accelerated by a potential difference of

Answer 1

Answer:

To have the same wavelength ,proton must be accelerated by a potential difference of 8v

mass of alpha = 4 amu and charge =2

mass of proton = 1amu and charge =1

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