Question

An alpha particle is moving perpendicular to the uniform
magnetic field of 0.5 T with the velocity 3x 105 ms -1.
What is the work done by the particle?
a. 15x105 )
b. Infinity​

Answer 1

Answer:

b) Infinite

Explanation:

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Answer 2

Given: Charge = 2e

           Magnetic field = 0.5T

           Velocity = 3×10⁵ ms⁻¹

To find: Work done by the particle

Solution:

• A force acting on a particle is said to perform work when there is a component of the force in the direction of motion of the particle.

• A charged particle carrying a charge q moving in a uniform magnetic field of magnitude B, the magnetic force acts perpendicular to the velocity of the particle. Here we say that no work is done by the magnetic force on the particle and hence, no change in the velocity of the particle can be seen.

Force acting on the particle is given by the formula, F = q(v×B)

Where q is the charge, v is the velocity, B is the magnetic field.

Then work done by the particle is equal to the W = F.d = FdCosθ

Since θ will be equal to 90°, and Cos90° = 0,

Therefore, the work done by the particle will be zero.