An alpha particle is projected onward a gold film with energy 5 mega electron volt.calculate the distance from nucleus of the gold to a point where alpha particle looses all its kinetic energy?
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Hi Hima
Here is your answer
K.E. = (A-4)Q/A, gives the kinetic energy from Q-value and mass number,A of mother nuclei,
Substituting the values,
48A = (A-4)50
=> 2A = 200
=> A = 100
Hope it helps
Here is your answer
K.E. = (A-4)Q/A, gives the kinetic energy from Q-value and mass number,A of mother nuclei,
Substituting the values,
48A = (A-4)50
=> 2A = 200
=> A = 100
Hope it helps
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