AN alpha-particle ( WHICH is a POSITIVELY charged Particle) ENTERS, A UNIFORM MAGNETIC FIELD AT RIGHT ANGLE TO IT. STATING the RELEVANT PRINCIPLE EXPLAIN IN WHICH DIRECTION WILL THIS alpha-particle?
Answers
Answered by
52
the force acting on an alpha particle in a uniform magnetic field is given by
F = qvBsinФ
where q = charge of alpha particle
v = velocity
B = strength of magnetic field
Ф = angle
here the particle is entering at right angle so Ф = 90 => sinФ = 1
=> alpha particle will experience F = qvB force which will provide centripetal acceleration and particle will move in a circle. for the direction of deflection we need to know the direction of magnetic field. in general, alpha particle will move perpendicular to the plane containing v and B.
if we assume B to be in +x direction & v in +y direction then α particle will be deflected in +z direction counterclockwise.
F = qvBsinФ
where q = charge of alpha particle
v = velocity
B = strength of magnetic field
Ф = angle
here the particle is entering at right angle so Ф = 90 => sinФ = 1
=> alpha particle will experience F = qvB force which will provide centripetal acceleration and particle will move in a circle. for the direction of deflection we need to know the direction of magnetic field. in general, alpha particle will move perpendicular to the plane containing v and B.
if we assume B to be in +x direction & v in +y direction then α particle will be deflected in +z direction counterclockwise.
Similar questions