Question

An alternating current, finde the average value of v(t)=6+2 sin; (2pi * 100 * t) volts

Answer 1

Answer:

160

Explanation:

6+2=8

8×2=16

16 + 100= 160

answer = 160

Answer 2

Given:

The alternating current is represented by

V(t) = (6+2) sin (2π 100t)

Find:

The average value of the above equation.

Solution:

The standard equation for potential difference of  an alternating current is ,

V = V₀ sin ωt                         ----------------- (i)

where V = Voltage

V₀ = Peak voltage

ω = Angular velocity

t = Time

Given equation, V(t) = (6+2) sin (2π 100t) ------------------- (ii)

Comparing (i) and (ii), we get

V = V(t)

V₀ = 6+2 = 8 V

ω = 2π(100) = 200π

t = t

Now, the average value of voltage is given by,

Vₐ = (2/π)V₀

Putting the values in above equation, we get

Vₐ = (2/3.14)×8

Vₐ = 16/3.14

Vₐ = 5.096 V

Hence, the average value is 5.096 V.

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