Question

An alternating current from a source is given by i= 10sin314t what is the effective value of current and frequency of source
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Answer 1

Answer:

CBSE Sample question paper 2021 phy q.4

i = i0sinwt

io is the max value of current, so the effective value (rms) will be io/√2 = 10/√2

10/√2 = 7.071 A

Now,

w= 2πf

comparing the eqn given in question,

w= 314

314=2πf

314= 2*3.14f

f = 100/2

thus, frequency will be 50 Hz