Question

An Alternating current is given by 10sin314t. measuring time from t=0,the time taken by the current to reach +10v for the second time is....​

Answer 1

The time taken by the current to reach +10V for the second time is 0.025 second.

Given:

Alternating current value I=10sin314t

To Find:

Time taken by the current to reach +10V for the second time.

Solution:

General, equation for an alternating current is given by

I=I₀sinωt

Given I=10sin314t

10=10sin314t

⇒Also, 3.14=π

⇒314=100π

⇒1=sin100πt

⇒100πt=sin⁻¹(1)

⇒100πt=(2nπ+π/2)       n=0,1,2 and so on

t= 1/200, 5/200, 9/200.....

t= 0.005s, 0.025s and .....

Thus, the time taken by the current to reach +10V for the second time is 0.025 second.

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