Question

an alternating current is represented by I=30 sin 377t find {1} frequency {2}time period.​

Answer 1

Answer:

1. Frequency is 60.03 Hz (approximately)

2. Time Period is 0.016 s (approximately)

Step-by-step explanation:

1. Given: The alternating current is represented by I = 30 sin 377t.

We know, I = Iₙ sinωt = Iₙ sin 2πf t

According to question,

⇒ 2πf = 377

⇒ f = $\frac{377}{2\pi }$ = $\frac{377}{2 X 3.14}$ = $\frac{377}{6.28}$ ≈ 60.03 Hz

∴ The frequency is 60.03 Hz approximately.

2. Now, Frequency f = 60.03 Hz

Time Period = $\frac{1}{f}$ = $\frac{1}{60.03}$ ≈ 0.016 s

∴ Time Period is 0.016 s approximately.