An alternating current source E = 100 sin (1000t) volt is connected through a inductor of 10 uH then
write down the equation of current.
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0
Answer:
I = 10sin(1000t) ampere
Answered by
13
Answer:
Explanation:
V=Vosin(Wt)
I=Iosinwt
Io=Vo/XL. XL=WL
I=100/1000×10×10^-6 sin(1000-π\2)
I=10000sin(1000W-π\2). Phase=-π\2 indicates in inductor I laggs over v
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