An alternating emf is represented as V = 10
sin 314t. The instantaneous emf at t = =
(1) 10V
(2) 4 V
(3) 5 V
(4) 6 V
600 S is
Answers
Answered by
25
Explanation:
Given An alternating emf is represented as V = 10 sin 314 t and frequency 50 hz. The instantaneous emf at t = 1/600 sec is
- Given Vo = 10 V, f = 50 hz
- We know that ω = 2 π f
- = 2 x π x 50
- = 100 π
- Given V = 10 sin 100π t
- Now V at t = 1/600 s = 10 sin (100π x 1/600)
- = 10 sin π / 6
- = 10 sin 30
- = 10 x 1/2
- = 5 Volts
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Answered by
22
An alternating emf can be represented by the equation
V(t) = sin ωt
where ω = 2f
f being the frequency
Here you can see in the give equation that ω = 314
314 = 2 x x f
f = 50 Hz
So for t =
V() = 10 sin 2xx50x
V() = 10 sin 100xx
V() = 10 sin
since sin = sin 30 =
V() = 10 x () = 5V
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