Question

An alternating emf of angular frequency omega w is applied across an inductance The instantaneous power developed in circuit has an angular frequency​

Answer 1

Answer:2w

Explanation:

The instantaneous values of emf and current in inductive circuits is given by the deduction as follows:

As we know Emf is

E= E0 sin wt

(greek alphabet omega will be represented by english alphabet w for convenience and sake of understanding as they look similar)

i = i0 sin (wt + π/2) current is always leading by phase of π/2

Hence as power is given by product of emf and current

P instantaneous = E*i= E0i0 sin wt * sin (wt-π/2)

=E0i0 sin wt ( sin wt cos π/2 - cos wt sin π/2)

E0i0 sin wt coswt (as sin π/2 is 0 and cos π/2 -0.5)

=1/2 E0i0 sin 2wt

Hence power will be 2w