Physics, asked by harshadph2004, 7 months ago

An alternating voltage given by e = 65 sin(314t) is connected across a pure resistor

of 100 Ω. Find the frequency of the source.

Answers

Answered by dushwanthdushwanth

0

Answer:

279

Explanation:

65(314)

379 subtract of 100

279

frequency of the source = 279

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