Question

An alternating voltage is connected in series with a resistance R and an inductance L If the potential drop across the resistance is 200 V and across the inductance is 150 V, then the applied voltage is(a) 350 V(b) 250 V
(c) 500 V(d) 300 V

Answer 1

answer : option (b) 250 V

explanation :

it is given that, potential drop across the resistance , $V_R$ = 200V

potential drop across the inductance, $V_L$ = 150V

we know, applied voltage in case of L-R circuit is given by, $V=\sqrt{V_R^2+V_L^2}$

= $\sqrt{200^2+150^2}$ V

= $\sqrt{40000+22500}$ V

= $\sqrt{62500}$ V

= 250 V

hence, applied voltage is 250V