An altidude ofa triangle is five third the length of its corresponding base if altitude be increased by 4 cm and the base decreased by 2 cm the area of the triangle remains the same find base and the altitudes of the triangle
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Answer:
12 cm and 20 cm.
Step-by-step explanation:
Let the base be '3a' and hence height should be 5/3 of 3a = (5/3 * 3a ) = 5a
Original height = 5a
Original base = 3a
When altitude is increased by 4 cm
and the base is decreased by 2 cm
New height = 5a + 4
New base = 3a - 2
Area of triangle = 1/2 * height * base
Here, area remains same:
= > 1/2 * 5a * 3a = 1/2 * (5a + 3)(3a - 2)
= > 5a*3a = (5a + 4)(3a - 2)
= > 15a² = 15a² - 10a + 12a - 8
= > 15a² - 15a² + 8 = 12a - 10a
= > 8 = 2a
= > 4 = a
Hence,
Original:
Height = 5a = 5(4) = 20
Base = 3a = 3(4) = 12
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