An altitude of a tri∠ is five- thirds the length of its corresponding
base. If the altitude is increased by 4 cm and the base is decreased by 2
cm, but the area of the tri∠ remains the same. Find the base and the
altitude of the tri∠ respectively.
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Answers
Answered by
4
let the base=t
then altitude=5t/3
according to the question
altitude is increased by 4
therefore ALTITUDE = 5t/3+4
base is decreased by 2
then BASE= t-2
given that area of triangle is same
1/2×base×altitude=1/2×BASE×ALTITUDE
1/2×t×5t/3=1/2×(t-2)×5t/3+4
5t square/3=(t-2)×5t+12/3
by solving this
t=12
base = 12
altitude = 20
Answered by
1
check here ur answer ......
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sorry kaur
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