An aluminium can of cylindrical shape contains 500 cm^3 of water. The area of the inner cross section of the can is 125 cm^2. All measurements refer to 10°c. Find the rise in the water level if the temperature increase to 80°c. The coefficient of linear expansion of aluminium= 23x10^-6/°c and average coefficient of volume expansion of water = 3.2x10^-4/°c.\
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# Answer- 0.0765cm
# Solution-
Let the co-efficient of linear expansion of aluminium be a and coefficient of volume expansion of water be y.
The initial area of the bottom A1 and initial volume of water is V1.
The final area is A2.
A2=A1(1+2aT)
because Coefficient of areal expansion = 2a
The final volume of water is V2
V2=V1(1+yT)
The initial length of water is= 500/125=4cm
Final length is= V1(1+yt)/A1(1+2at)
Putting the values we get
Final length=4.0765 cm
Hence
Increase in the water level =(4.0765-4)=.0765 cm
# Solution-
Let the co-efficient of linear expansion of aluminium be a and coefficient of volume expansion of water be y.
The initial area of the bottom A1 and initial volume of water is V1.
The final area is A2.
A2=A1(1+2aT)
because Coefficient of areal expansion = 2a
The final volume of water is V2
V2=V1(1+yT)
The initial length of water is= 500/125=4cm
Final length is= V1(1+yt)/A1(1+2at)
Putting the values we get
Final length=4.0765 cm
Hence
Increase in the water level =(4.0765-4)=.0765 cm
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